00:01
So we want to find out how much energy it's going to take to heat up 245 liters, and assuming that each liter equals one kilogram, 245 kilograms of water.
00:15
So that's our mass, m.
00:17
From an initial temperature, t -sive -i, of 10 degrees, to a final temperature of 45 degrees.
00:23
The specific heat of water is 4 ,186 joules per kilogram times degrees celsius.
00:27
And then we want to know how long it would take if the heater output is 9 ,500 watts.
00:34
So power here is 9500 watts.
00:36
Okay.
00:37
So for part a, the amount of heat energy required is given by equation 14 -2.
00:43
Okay.
00:45
So according to equation 14 -2, q, the energy, is equal to the mass times the civic heat constant c times the change in temperature delta t...