00:01
Suppose that f at 0 is 1, f at 0 .5 is 2 .5, f at 1 is 2, and f at 0 .25 and f at 0 .75 both are equal to alpha.
00:19
Using the trapezoidal rule with force of intervals gives the integral from 0 to 1 of f is 1 .75.
00:29
Then find the value of alpha in the real numbers.
00:34
So, here we have interval 0, 1, where we calculate the integral here.
00:46
So, our interval of integration is 0, 1.
00:51
We have force of intervals of equal width.
00:57
And so, the length of any of the force of intervals is equal to the length of the interval of integration, 1 minus 0, divided by the number of subintervals, 4.
01:10
That is 1 fourth, which is 0 .25.
01:16
That means that the interval 0, 1 is divided in four equal parts like this...