Question

Example # 1 - Calculate the voltage $V_x$ across the $20\Omega$ resistor using KCL. Solution: $20 \Omega$ $60 \Omega$ + $V_x$ - $30 \Omega$ 0.5 A + 10 V - $30 \Omega$

Name: example 1 calculate the voltage vx across the 20omega resistor using kcl solution 20 omega 60 omega vx 30 omega 05 a 10 v 30 omega 50137
Uploaded: 2022-12-06T10:12:35-08:00
Duration: 4 min 23 s
Channel: Madhur L
Description: example 1 calculate the voltage vx across the 20omega resistor using kcl solution 20 omega 60 omega vx 30 omega 05 a 10 v 30 omega 50137

          Example # 1 - Calculate the voltage $V_x$ across the $20\Omega$ resistor using KCL.
Solution:
$20 \Omega$
$60 \Omega$
+ $V_x$ -
$30 \Omega$
0.5 A
+ 10 V -
$30 \Omega$

Added by Victoria N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

12/06/2022

Step 1

Let $V_1$ be the voltage at the node where the $30\Omega$ resistor, the current source, and the $20\Omega$ resistor are connected. Let $V_2$ be the voltage at the node where the $20\Omega$ resistor, the voltage source, and the $60\Omega$ resistor are connected. Show more…

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Example # 1 - Calculate the voltage $V_x$ across the $20\Omega$ resistor using KCL. Solution: $20 \Omega$ $60 \Omega$ + $V_x$ - $30 \Omega$ 0.5 A + 10 V - $30 \Omega$