Question

Find the intercepts of the plane given by the equation 3x + 5y - 2z - 4 = 0. Rewrite the equation of the plane in the format of the intercept form of the plane equation. 3x + 5y - 2z = 4 1 = 3/4x + 5/4y + -2/4z a = 4/3, b = 4/5, and c = 4/-2 = -2. Thus the intercepts of this plane are (4/3, 0, 0), (0, 4/5, 0), and (0, 0, -2).

          Find the intercepts of the plane given by the equation 3x + 5y - 2z - 4 = 0.
Rewrite the equation of the plane in the format of the intercept form of the plane equation.
3x + 5y - 2z = 4
1 = 3/4x + 5/4y + -2/4z
a = 4/3, b = 4/5, and c = 4/-2 = -2. Thus the intercepts of this plane are
(4/3, 0, 0), (0, 4/5, 0), and (0, 0, -2).

Find the intercepts of the plane given by the equation 3x + 5y - 2z - 4 = 0.
Rewrite the equation of the plane in the format of the intercept form of the plane equation.
3x + 5y - 2z = 4
1 = 3/4x + 5/4y + -2/4z
a = 4/3, b = 4/5, and c = 4/-2 = -2. Thus the intercepts of this plane are
(4/3, 0, 0), (0, 4/5, 0), and (0, 0, -2).

Added by Kenny B.

Calculus an Applied Approach

Ron Larson, David C, Falvo 8th Edition

Chapter 7

Instant Answer

Solved by Expert Dominique Jan Tan

01/18/2024

Step 1

Certainly! Let's break down the process of finding the intercepts of the plane given by the equation \(3x + 5y - 2z - 4 = 0\) and rewriting it in intercept form. Show more…

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