Example 3-9. Twenty-five books are placed at random in a shelf. Find the probability that a particular pair of books shall be: (i) Always together, and (ii) Never together. Solution. Since 25 books can be arranged among themselves in 25! ways, the exhaustive number of cases is 25!
Added by Kevin B.
Close
Step 1
Step 1: The total number of ways to arrange 25 books is 25!. Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 75 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
n books, say book 1 to book n, are arranged randomly on a shelf from left to right, so that each of the n! permutations is chosen with the same probability. What is the probability that book 1 and book 2 are adjacent? Example: One outcome in this event (when n = 5) is 35214.
Sri K.
In how many ways, can 10 different books be arranged on a shelf so that a pair of books will be (a) always together and (b) never together?
Adi S.
Christopher D.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD