Consider the neutron capture by Al27 to form the compound nucleus Al28 - What is the excitation energy of the compound nucleus? (assume that the neutron kinetic energy is 1 MeV) M(n) = 1.00898 u , M(Al27) = 26.99008 u, M(Al28) = 27.99077 u
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Given: Mass of neutron, Mn = 1.00898 u Mass of Al-27, M(Al-27) = 26.99008 u Mass of Al-X, M(Al-X) = 27.99077 u Q value (Q) = [M(Al-X) - (M(Al-27) + Mn)] * c^2 Q = [27.99077 - (26.99008 + 1.00898)] * (931.5 MeV/u) Q = 0.99171 * 931.5 Q = 923.89 MeV Show more…
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