Excess (NH4)2SO4 was added to a 75.0 mL solution containing BaCl2 (MW=208.23 g/mol). The resulting BaSO4 (MW=233.43 g/mol) precipitate had a mass of 0.2384 g after it was filtered and dried. What is the molarity of BaCl2 in the solution?
Added by Audrey M.
Step 1
Given mass of BaSO4 = 0.2384 g Molar mass of BaSO4 = 233.43 g/mol Number of moles of BaSO4 = Mass / Molar mass Number of moles of BaSO4 = 0.2384 g / 233.43 g/mol Number of moles of BaSO4 = 1.0210 x 10^-3 mol Show more…
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