Question

Exer. 49-58: Find the center and radius of the circle with the given equation. 49 $x^2 + y^2 - 4x + 6y - 36 = 0$ 50 $x^2 + y^2 + 8x - 10y + 37 = 0$ 51 $x^2 + y^2 + 4y - 7 = 0$ 52 $x^2 + y^2 - 10x + 18 = 0$ 53 $2x^2 + 2y^2 - 12x + 4y - 15 = 0$ 54 $4x^2 + 4y^2 + 16x + 24y + 31 = 0$ 55 $x^2 + y^2 + 4x - 2y + 5 = 0$ 56 $x^2 + y^2 - 6x - 4y + 13 = 0$ 57 $x^2 + y^2 - 2x - 8y + 21 = 0$

          Exer. 49-58: Find the center and radius of the circle with
the given equation.
49 $x^2 + y^2 - 4x + 6y - 36 = 0$
50 $x^2 + y^2 + 8x - 10y + 37 = 0$
51 $x^2 + y^2 + 4y - 7 = 0$
52 $x^2 + y^2 - 10x + 18 = 0$
53 $2x^2 + 2y^2 - 12x + 4y - 15 = 0$
54 $4x^2 + 4y^2 + 16x + 24y + 31 = 0$
55 $x^2 + y^2 + 4x - 2y + 5 = 0$
56 $x^2 + y^2 - 6x - 4y + 13 = 0$
57 $x^2 + y^2 - 2x - 8y + 21 = 0$

Exer. 49-58: Find the center and radius of the circle with
the given equation.
49 x^2 + y^2 - 4x + 6y - 36 = 0
50 x^2 + y^2 + 8x - 10y + 37 = 0
51 x^2 + y^2 + 4y - 7 = 0
52 x^2 + y^2 - 10x + 18 = 0
53 2x^2 + 2y^2 - 12x + 4y - 15 = 0
54 4x^2 + 4y^2 + 16x + 24y + 31 = 0
55 x^2 + y^2 + 4x - 2y + 5 = 0
56 x^2 + y^2 - 6x - 4y + 13 = 0
57 x^2 + y^2 - 2x - 8y + 21 = 0

Added by Carolina M.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Piyush Kumar Gupta

03/23/2022

Step 1

x^2 - 6x + y^2 - 4y = -13 (x^2 - 6x + 9) + (y^2 - 4y + 4) = -13 + 9 + 4 (x - 3)^2 + (y - 2)^2 = 0 Show more…

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Exer. 49-58: Find the center and radius of the circle with the given equation. x^(2)+y^(2)-6x-4y+13=0 Exer. 49-58: Find the center and radius of the circle with the given equation. 49x2+y2-4x+6y-36=0 5O x2+ y2+8x-10y+37=0 51x2+y+4y-7=0 52x2+y2-10x+18=0 53 2x2+2y2-12x+4y-15=0 54 4x2+ 4y+ 16x+ 24y+31=0 55 x2+y2+4x-2y+5=0 56x+y2-6x-4y+13=0 x-8v+21=0