00:01
Hi, in this question, they're saying that for a 16 qam modulator with an input data rate, so input is given as 20 mbps and a carrier frequency of 100 megahertz, determine the minimum double -size nyquist bandwidth and the baud.
00:22
So we have to determine its bandwidth efficiency as well.
00:27
Now, first of all, the rate in both the i and q channels is equal to one half of the transmission bit rate.
00:36
Or we can write fbq equals to fbi equals to fb by 2.
00:45
Therefore, we'll have this as 20 mbps by 2.
00:51
So we get this as 10 mbps.
00:54
Now, the highest fundamental frequency present in either balanced modulator, that is fa, is given as fbq by 2.
01:05
So we'll have half of this, which is 5 mbps.
01:09
So the output wave from each balanced modulator is given as sine of 2 pi fat into sine of 2 pi fct...