Question

A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the mole fraction of H3PO4. (Assume water has a density of 1.00 g/mL.) MM H3PO4 = 97,994 g/mol MM H2O = 18,016 g/mol

          A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the mole fraction of H3PO4. (Assume water has a density of 1.00 g/mL.)

MM H3PO4 = 97,994 g/mol
MM H2O = 18,016 g/mol

$A solution of phosphoric acid was made by dissolving 8.00 g of H3PO4 in 100.0 mL of water. Calculate the mole fraction of H3PO4. (Assume water has a density of 1.00 g/mL.) MM H3PO4 = 97,994 g/mol MM H2O = 18,016 g/mol$

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Chemistry

Steven S. Zumdahl, Susan A. Zumdahl,… 10th Edition

Chapter 11

Instant Answer

Solved by Expert Shalini Tyagi

02/27/2025

Step 1

Given mass of $ \mathrm{H}_{3} \mathrm{PO}_{4} = 8.00 \, \text{g} $. Molar mass of $ \mathrm{H}_{3} \mathrm{PO}_{4} = 97.994 \, \text{g/mol} $. \[ \text{Moles of } \mathrm{H}_{3} \mathrm{PO}_{4} = \frac{8.00 \, \text{g}}{97.994 \, \text{g/mol}} = 0.0816 \, Show more…

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