00:02
According to question, a cylinder is placed into the water, which will be looked like by this figure.
00:08
So this is what the water surface, which is at 3 meter above from the floor, and the cylinder is placed in such a way that it touching to the water surface and this floor of this tank.
00:23
So according to question, we need to find the reaction at point b, let's say rb.
00:30
And reaction at point a, let's say ra.
00:35
While according to cohesion, it is given that the diameter of the cylinder is 3 meter, length of the cylinder is 4 meter, weight of the cylinder that is w is equals to 196 .2 kiloons.
00:52
If we convert in neuters, it will come out 196 to 0 .0 neuters.
01:00
So to find this horizontal reaction and vertical reaction, we need to find the horizontal and vertical forces exerting by the water onto the cylinder.
01:10
So first of all, let's suppose the f of x be the horizontal force exerted by the water, which will be equals to the force exerted on this vertical portion.
01:20
I mean to say this much of arc, that is b -o -c.
01:24
So it will be equals to row g a into edge now we need to find this area that is boc so actually it will be look like a rectangle in then into the front so this will be equals to the length into breadth and that would be equest to now here length will be three and breadth will be four so three fours are twelve it will comes out twelve meters square while if you see the height, so height is nothing but the half of the diameter, that is d divided by 2.
02:02
So it will be equals to 3 by 2 which is equals to 1 .5 meter...