Refer to the figure below. The distance L is 4 m and the...

Refer to the figure below. The distance L is 4 m and the mass of the girl is 55 kg. 1. If the mass of the boy is 75 kg, where should he sit on the beam to balance the system about the support point? (Hint: for the system to be balanced the net torque must be equal zero) 2. Calculate the magnitude of the normal force n if the beam has a mass of 12 kg 3. If the boy is sitting at a distance of 1.46 m from the support, calculate the net torque of the system about an axis going through the left end of the beam

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00:01 Hello students in this question we are given a figure of a caesar whose distance is length we can say is 4 meters and the mass of the girl is here 55 kg so this is basically small m and let us see the figure first so where this is the figure and the first part we have we have been given if the mass of the boy that is the value of capital m is 75 kg then where should he sit on the beam to balance the system about the support point so let the distance of the boy from the private point be x here it is represented x so if we find if we find the torque about this private point so tau about private point so it will be town net will be equal to zero because we have to balance the beam so so if we take the anti -clockwise direction in positive, so the m -g, that is the weight of gull multiplied by the distance.

01:12 So here distance is 2 meters and this force will be 0 taught due to this because it lies on the p -1 point.

01:21 So anti -clockwise is positive over there.

01:23 And this is this forces clockwise over here.

01:26 So this will be negative minus capital m -g that is the weight of the boy.

01:30 Under distances here x is equal to 0 so we have here m 2 times 2 small m multiplied by g is equal to capital m g multiplied by x so here g and g will cancel the 2 small m is equal to capital m multiplied by x over here so x will come out to be 2 times small m over capital m so x is equal to 2 times this is 55 over small m over capital m so it is 75 so here x comes out to be so it is 1 .47 meters so the boys should sit 1 .47 meter from the private point to balance the beam now in the second part we have to calculate the magnitude of normal force n if the beam has mass 12 kg so we will since it is in equilibrium the system is in we will balance the forces on the y axis or the vertical forces so here the upward forces m over n over here so we write n here is equal to so there is only one upward force and this force balances three forward forward that is small m multiply by g plus mass of the beam m m pl multiply by g plus capital m g plus capital m g plus capital m g so n is equal to here this is the mass of the girl is 55 multiplied 9 .8 plus the mass of the beam it is given to a switch 12 multiplied 9 .8 plus mass of the wave which is 75 multiplied 9 .8...

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