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In this problem, we are meant to solve all of these inequalities.
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However, that would make the video very long, and it would be too big to upload.
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So i've chosen a few examples out of this block for us to work with.
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So let's get started with number one, where we have x times x minus 4 times x plus 2 is greater than 0.
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So this has already been factored for us.
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So what we can do is split up those factors into two separate inequalities.
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And that's going to be a recurring theme throughout this video.
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So now we just have to solve for x, and so we have to add four to both sides.
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And so we will have x is greater than four.
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And over here we have to subtract two.
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So we have x is greater than minus two.
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Now if you're going to draw this on a number line, draw our number line here, put zero kind of sort of in the middle.
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We have a positive four and a minus two.
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We have to go at least out that far.
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So we have one, two, three, four, there's four, there's two.
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And then we have minus one, minus two.
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So we have, we want all values where x is greater than four.
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So we don't have an equal sign.
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So the actual circle is going to be a bigger circle.
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It's going to be open.
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And then we want all values greater than that.
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So all values this way on the number line.
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Now for the other one, we have x is greater than minus two.
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So here's minus 2, and it's not equal.
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So we want an open loop.
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We want all values that are greater than that one.
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So we go that way.
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So the actual answer to this problem are all values of x that are greater than 4, and remember, they have to also solve the second part of the inequality greater than minus 2.
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And if you notice this inequality sign, the open end is facing towards the x.
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So we want to keep it that way as well.
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So we only need values that are greater than minus 2 and greater than 4 to solve the problem.
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So let's check this out and let's see y for a second.
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So let's put in the value of 0.
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Let's let x equal 0, just to give us a little check.
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So we have 0 minus 4 times 0 plus 2, and this has to be greater than 0.
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So we'll end up with minus 4 times 2, which equals minus 8.
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And that is definitely not greater than zero.
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So this is why they have to be and.
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So the correct visual on the number line, we'll put the zero here.
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And we'll have one, two, three, four.
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We'll put a two there and a four there.
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And keep our open zero.
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And we'll actually have all values going this way to solve the problem.
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Number five, x squared minus five x plus four is greater than zero.
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So this one, we actually have to factor ourselves.
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So let's go ahead and do that.
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We'll have x and x.
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And for our factors of four, we have two times two and one times four.
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And we have to get to a total of minus five.
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Well, if we add these two numbers together, that will actually get us five.
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So we'll put a four over here and a one over here.
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It doesn't actually matter, but we can do it this way.
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So we need a minus five and a minus four.
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So let's put minus signs in both of those because minus four plus minus one equals minus five, and minus one times minus four is equal to positive four.
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So all of these are greater than zero.
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So we'll have x minus one is greater than zero, and x minus four is greater than zero.
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So we want all values of x that are greater than one and all values of x that are greater than four.
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And as we saw on the one above, they have to solve both of these.
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So when we draw it on the number line, you can put our zero here and we'll have one, two, three, four.
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But remember, they have to solve both.
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So we'll have a big circle here to represent values greater than four.
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And you could put a circle here to represent values greater than one.
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But remember, they have to solve both inequalities, and two and three will not solve this inequality.
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So the actual number line should look like this.
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We'll have a zero, and we'll have one, two, three, four, and we'll just have this big circle at the four, and an arrow pointing that way.
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Number 11, three x squared plus 10x minus eight is less than or equal to zero.
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So just like before, let's factor this one out.
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So we'll put three x here and x here.
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Now our factors of eight are eight times one and two times four.
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We have to get to a 10.
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So if we do four times three, that'll get us to 12, and then we can subtract out two, and that'll get us 10.
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So we have to put the four here, and then we have to put the two here.
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We need a positive value and a negative eight, so the positive value will go with plus four, and the negative.
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And the sign will go with 2.
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So now we have 3x minus 2 is less than or equal to 0, and x plus 4 is less than or equal to 0.
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So let's solve this left one first.
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We'll have 3x is less than or equal to positive 2, and x is less than or equal to positive 2 thirds.
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Over here, we'll just have x is less than or equal to minus 4.
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So on the number line, we have a negative 4 and a positive 2 thirds, and we'll put the 0 here...