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Hello students, in this question, we have to write the mechanism for the reaction between ethyl iodide and sodium cyanide.
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The reaction of the ethyl iodide and the sodium cyanide follows sn1 mechanism i .e.
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The substitution nucleophilic unimolecular.
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Here, the substitution of the nucleophile i .e.
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Cyanidine takes place and the right determining step consists of only one molecule.
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The first step here is the cleavage of the carbon iodine bond.
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This bond will cleave and the iodine will eliminated as iodine ion and result in the formation of carbocation i .e.
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Hydrogen carbon carbon, hydrogen and another hydrogen and hydrogen with a positive charge over here.
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The next step is attack of nucleophile.
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The carbon in the cyanide will attack the positive charge of the carbocation and result in the formation of our unimolecular intermediate i .e...