Question

Experiment 23 Advanced Study Assignment: Determination of the Equilibrium Constant for a Chemical Reaction A student mixes 2 mL of 2 M Fe(NO3)2 with 3 mL of 0.10 M KSCN and 2 mL of water. She finds that in the equilibrium mixture, the concentration of FeSCN2+ is 7.0 * 10^-4 M. Find K for the reaction Fe^2+ (aq) + SCN^- (aq) ⇌ FeSCN2+ (aq). Step 1: Find the number of moles of Fe^2+ and SCN^- initially present. moles Fe^2+ = moles SCN^- = Step 2: How many moles of FeSCN2+ are in the mixture at equilibrium? What is the volume of the equilibrium mixture? moles FeSCN2+ = volume of equilibrium mixture = Step 3: How many moles of Fe^2+ and SCN^- are used up in making the FeSCN2+? moles Fe^2+ used up = moles SCN^- used up = Step 4: How many moles of Fe^2+ and SCN^- remain in the solution at equilibrium? moles Fe^2+ remaining = moles SCN^- remaining = Step 5: What are the concentrations of Fe^2+, SCN^-, and FeSCN2+ at equilibrium? [Fe^2+] = [SCN^-] = [FeSCN2+] = Step 6: What is the value of K for the reaction? K =

          Experiment 23 Advanced Study Assignment: Determination of the Equilibrium Constant for a Chemical Reaction
A student mixes 2 mL of 2 M Fe(NO3)2 with 3 mL of 0.10 M KSCN and 2 mL of water. She finds that in the equilibrium mixture, the concentration of FeSCN2+ is 7.0 * 10^-4 M. Find K for the reaction Fe^2+ (aq) + SCN^- (aq) ⇌ FeSCN2+ (aq).

Step 1: Find the number of moles of Fe^2+ and SCN^- initially present.
moles Fe^2+ = 
moles SCN^- = 

Step 2: How many moles of FeSCN2+ are in the mixture at equilibrium? What is the volume of the equilibrium mixture?
moles FeSCN2+ = 
volume of equilibrium mixture = 

Step 3: How many moles of Fe^2+ and SCN^- are used up in making the FeSCN2+?
moles Fe^2+ used up = 
moles SCN^- used up = 

Step 4: How many moles of Fe^2+ and SCN^- remain in the solution at equilibrium?
moles Fe^2+ remaining = 
moles SCN^- remaining = 

Step 5: What are the concentrations of Fe^2+, SCN^-, and FeSCN2+ at equilibrium?
[Fe^2+] = 
[SCN^-] = 
[FeSCN2+] = 

Step 6: What is the value of K for the reaction?
K =

Added by Diego K.

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