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Experiment 7: Qualitative Analysis by Paper Chromatography Data Sheet Data and Observations I. Extraction of Ferromagnetic Material Mass of Total Cereal Mass of Clean, Dry Magnetic Stir Bar Mass of Magnetic Stir Bar plus the Metal Filings Mass of the Metal Filings (Experiment Yield) II. Identification of Ferromagnetic Material Calculations 1. Calculate the theoretical yield of iron in your experimental sample of Total cereal based on the manufacturer's claim that a 30-gram serving of cereal contains 100% of the recommended daily intake. 30g \rightarrow 0.0144 g. of iron 10.082 g cereal \rightarrow (0.0144 \times 10.082)/30 = 0.00483936 g. of iron 2. Assuming all of the ferromagnetic material collected from the cereal is iron, calculate the percent yield of iron using the following equation: Percent Yield = (Experimental Yield/Theoretical Yield) \times 100%. (0.0018 / 0.00483936) \times 100 = 37.19% percentage yield Results and Discussion of Results State the results for each part of the experiment, including the results of the chemical tests for iron and nickel. Which aspects of the experiment likely contributed to a percentage yield greater than or less than 100 percent?

          Experiment 7: Qualitative Analysis by Paper Chromatography
Data Sheet
Data and Observations
I. Extraction of Ferromagnetic Material
Mass of Total Cereal
Mass of Clean, Dry Magnetic Stir Bar
Mass of Magnetic Stir Bar plus the Metal Filings
Mass of the Metal Filings (Experiment Yield)
II. Identification of Ferromagnetic Material
Calculations
1. Calculate the theoretical yield of iron in your experimental sample of Total cereal based on the
manufacturer's claim that a 30-gram serving of cereal contains 100% of the recommended daily intake.
30g \rightarrow 0.0144 g. of iron
10.082 g cereal \rightarrow (0.0144 \times 10.082)/30
= 0.00483936 g. of iron
2. Assuming all of the ferromagnetic material collected from the cereal is iron, calculate the percent yield of
iron using the following equation: Percent Yield = (Experimental Yield/Theoretical Yield) \times 100%.
(0.0018 / 0.00483936) \times 100 = 37.19% percentage yield
Results and Discussion of Results
State the results for each part of the experiment, including the results of the chemical tests for iron and nickel.
Which aspects of the experiment likely contributed to a percentage yield greater than or less than 100 percent?

Experiment 7: Qualitative Analysis by Paper Chromatography
Data Sheet
Data and Observations
I. Extraction of Ferromagnetic Material
Mass of Total Cereal
Mass of Clean, Dry Magnetic Stir Bar
Mass of Magnetic Stir Bar plus the Metal Filings
Mass of the Metal Filings (Experiment Yield)
II. Identification of Ferromagnetic Material
Calculations
1. Calculate the theoretical yield of iron in your experimental sample of Total cereal based on the
manufacturer's claim that a 30-gram serving of cereal contains 100% of the recommended daily intake.
30g →0.0144 g. of iron
10.082 g cereal →(0.0144 ×10.082)/30
= 0.00483936 g. of iron
2. Assuming all of the ferromagnetic material collected from the cereal is iron, calculate the percent yield of
iron using the following equation: Percent Yield = (Experimental Yield/Theoretical Yield) ×100%.
(0.0018 / 0.00483936) ×100 = 37.19% percentage yield
Results and Discussion of Results
State the results for each part of the experiment, including the results of the chemical tests for iron and nickel.
Which aspects of the experiment likely contributed to a percentage yield greater than or less than 100 percent?

Added by Trinidad K.

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