00:01
Question 8 deals with the efficient event resulting by a neutron absorbed by uranium 238 to produce plutonium 239.
00:14
On this question, we want to find, at least for part a, we want to find how much plutonium is formed for a 30 % efficient, here you're given by little e, 30 % efficient nuclear plant in which for each reaction, 0 .6 .9.
00:31
Neutrons are absorbed, rather than one per each reaction.
00:38
In part a, we want to find the mass that is produced.
00:44
Well, i'm going to start with the total energy.
00:48
Well, actually, i want to start with power, because we're given power initially for the scenario.
00:52
So that power is equivalent to energy over a rate of time or time region.
01:01
While we're not given energy, we're given energy per fission event.
01:07
And we represent that as times the number of events that occur.
01:13
In this scenario, we only consider a successful event, so that's 30 % efficiency.
01:20
And for each scenario, we only obtain 0 .6 neutrons per event.
01:26
And all of it has to be per time to maintain our time here.
01:30
So i'll just put times one over time as an extra term.
01:34
It can be placed on anyone, but yeah, let's leave it over on the side for now.
01:42
Well, for the number, and we know what the number of 50s.
01:45
Evasion events or number of atoms, we can just base it off of the mass of our sample over the molar mass times avagadro's number and a.
01:53
So i'm going to replace this term now here, which, of course, we're trying to solve in part a for this mass term.
02:02
So i have, again, energy proficient event times the mass over molar mass times avagadro's number times each of these.
02:12
And i'll put this just over t.
02:15
It doesn't really matter where this one over t term goes...