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Hello students, in this question we have to prepare chloropentane from alkane and alkene.
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First of all we are going to prepare the chloropentane from alkane.
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It follows the free radical mechanism.
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The first step is the initiation step i .e.
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Chlorine has been split into two chloride free radical.
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So this chloride free radical will attack the pentane i .e.
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Ch3ch2ch2ch2ch3.
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This has been attacked by the chlorine free radical so that hcl will be eliminated leaving the free radical over in the pentane group i .e.
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Ch3ch2ch2ch2ch2.
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So this ch2.
00:56
Has been attacked by the hcl again.
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It will be the plus hcl.
01:01
So that is ch3ch2ch2ch2ch2.
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So this hydrogen will eliminated as hydrogen free radical and this chloride ion will attack and become chloropentane i .e.
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Ch3ch2ch2ch2ch2cl...