00:01
We're given t of t, and that is 71e to the negative 0 .0514t as our function, and that represents coffee cooling room temperature.
00:13
We want to find in a the temperature 16 minutes after it started to cool, so we're just going to put in 16 for t, raise e to the negative 0 .0514 times 16 power, and then multiply by 71, and then, sorry, add 23.
00:45
And you're going to get 54 .1956879.
00:53
So that would be about 54 .2 degrees.
01:00
We want to find the horizontal asymptote.
01:10
So for this problem, we could graph that function.
01:18
And i'm just going to sketch this for you in one second and if you graph this you're going to see your initial temperature is 94 degrees and then as time goes on your function is going to drop and then flatten out at 23 so your your horizontal asymptote is going to be y is equal to 23.
02:35
Now we want to write down room temperature.
02:44
So room temperature is that horizontal asymptote...