00:01
All right, they want us to find the quotient in the remainder using long division, no synthetic division, which we couldn't use anyway.
00:06
It's on the form of x minus c.
00:09
So this is a little bit interesting.
00:11
I think it's the first one i've seen where, first of all, the three in term, right, the three x.
00:16
And how do i make it an x to the third? i think this is the first time where i've seen.
00:20
You have to multiply three times one third to make it one.
00:25
And then you multiply an x times an x squared to make it an x to the third.
00:30
Okay, one third, that will end up being x to the third, just like we wanted it to be.
00:34
One third x squared times six.
00:36
Well, one third time six.
00:38
It's six divided by three is two x squared.
00:43
I like to put a parentheses around the entire thing being subtracted.
00:49
So x third minus x to the third cancels out.
00:52
Three x squared minus two x squared leads us just with one x squared.
00:57
Let's bring down the 4x, and i can already tell something's going to be a little bit complicated.
01:02
Here's what's going to be complicated.
01:04
I'm going to have to multiply by another third because three times a third is going to get me to that coefficient of one.
01:13
One third and another x is going to get me to x squared.
01:17
So that's how i'm going to get to an x squared here.
01:21
This is multiplied by one -third x up there on my quotient.
01:24
Here's what's complicated as i can already see.
01:28
Oh, never mind.
01:29
One -third times six is a two again...