00:01
In this problem, we need to express the negation of each of the given statements.
00:06
Now, the first statement is, for all x minus 2 less than x, less than 3.
00:18
So, we need to write the negation of this statement.
00:23
Now, the negation of a statement of the form for all x, then we have something.
00:29
We will have there exists and x says that naught of whatever is given.
00:36
So this will be the negation.
00:39
So we need to make sure that we do not have the negation symbol.
00:44
So let us simplify this.
00:45
So this will be there exists and x says that naught of minus 2 less than x, less than 3 means minus 2 is less than x and x is less than 3.
00:57
So we need to negate that.
01:01
So by d morgan's laws, the negation of p and q is not p or not q.
01:09
So we need to write the negation of minus 2 less than x, so that will be minus 2 greater than or equal to x.
01:16
Then instead of and we have or, then we have not of x less than 3.
01:21
So that will be x is greater than or equal to 3.
01:24
So this is our negation.
01:25
There exists x minus 2 greater, greater, equal to x or x is greater equal to 3.
01:31
Then for the next statement, the next statement is for all x, 0 is less than or equal to x is less than 5.
01:43
So the negation will be there exists an x, so is that not 0 less than or equal to x less than 5.
01:58
So this is there exists, there exist and x is that knot of 0 is less than or equal to x and x is less than 5.
02:11
So we use d.
02:13
Morgan's law and the negation over here will be of the form not p or not q...