00:01
Here mass of alloy is equal to mass of capsule and alloy that is 0 .271 grams minus mass of gelatin capsule 0 .112 gram.
00:16
We will get 0 .159 grams and mass of displaced water is equal to mass of beaker and displaced water that is 307 .712 grams minus mass of empty beaker 141 .209 grams.
00:38
We will get 166 .503 grams.
00:44
Also at 21 degree celsius density of water is 0 .997992 gram per ml.
00:53
So here we can write density of water is equal to mass of displaced water that is 166 .503 gram divided by volume.
01:06
So this is equal to 0 .997992 gram per ml.
01:10
From this we can get volume is equal to 166 .838 ml.
01:16
So this will be the volume of displaced water.
01:21
And next we can calculate the volume of hydrogen gas.
01:24
Volume of hydrogen gas is equal to volume of displaced water that is this 166 .8 this ml it will be 0 .166838 liter and we can calculate the temperature of hydrogen gas in kelvin.
01:44
So here temperature is given 21 degree celsius.
01:48
So it will be 21 plus 273 will get 294 kelvin.
01:55
This is the temperature of hydrogen gas and also vapor pressure is given 18 .650 mm hg and from this we can calculate the pressure of dry hydrogen gas is equal to parameter pressure that is 745 .9 mm hg minus pressure of water...