Question

F1 = 60 lb ?2 1 1 y x 60° F2 = 70 lb 45° F3 = 50 lb For the diagram shown above, determine the magnitude of the resultant force (sum of the forces) and its direction measured counterclockwise from the positive x-axis. The direction is the angle the resultant vector does with positive x-axis.

          F1 = 60 lb
?2
1
1
y
x
60°
F2 = 70 lb
45°
F3 = 50 lb
For the diagram shown above, determine the magnitude of the resultant force (sum of the forces) and its direction measured counterclockwise from the positive x-axis. The direction is the angle the resultant vector does with positive x-axis.

F1 = 60 lb
?2
1
1
y
x
60°
F2 = 70 lb
45°
F3 = 50 lb
For the diagram shown above, determine the magnitude of the resultant force (sum of the forces) and its direction measured counterclockwise from the positive x-axis. The direction is the angle the resultant vector does with positive x-axis.

Added by William G.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Charles Maxwell

09/06/2023

Step 1

For F = 60 lb, the force is along the positive X-axis, so its components are: Fx = 60 lb Fy = 0 lb For F3 = 50 lb, the force is along the positive Y-axis, so its components are: Fx = 0 lb Fy = 50 lb For Fz = 609 lb at an angle of 9° counterclockwise from the Show more…

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For the diagram shown above, determine the magnitude of the resultant force (sum of the forces) and its direction measured counterclockwise from the positive x-axis. The direction is the angle the resultant vector does with positive x-axis.