00:01
All right, so let's say we have a point a here under consideration, and we're told that the electric field at point a kind of looks like this, where we have, or we have several possibilities, anyway, of what the electric field could look like.
00:16
And we're told we a charge of a value of eight nanocouams is placed at point a, and it experiences a force that we are told as a vector is, we'll say negative 48 microneyutons in the x direction and then 48 microneyotons in the y direction right and so of the directions that we've drawn here where we drew eight of them which one best indicates the direction of the electric field so it's a positive charge and so the electric field is going to be in the same direction as the force and so it's the x and y components have the same magnitude but the component is negative so it's going to be this component right here which is labeled h in the picture and then the electric field at that point as a vector is just going to be the force divided by the charge and so if we look at what those are we'll have negative 48 micronutons divided by eight nanoculums and then 48 micronutons divided by 8 nanoculums and then 48 micronutons divided by eight nanoculams.
01:35
And so if we put those in units of newton's per coulom, we should get like negative 6 ,000 newtons per coulom in the x direction, and then 6 ,000 newtons per coulom in the y direction.
01:52
That's our electric field.
01:53
And then we also want to know what's the magnitude of the electric field.
01:56
Well, the magnitude is just basically going to be 6 ,000 times the square root of two.
02:02
So it should be 8 ,485 .3 newtons per koum.
02:08
And that's because both components have the same magnitude.
02:11
They have the same value, just ones in a different direction.
02:15
And then continuing on, now this charge has moved very far away in a tiny plastic ball with a charge of q, let's call it q prime, of negative 9 nanocouons, is placed at the same location...