00:01
In this question, you look at torques, right? now you have two forces, f1 and f2, right? and you have this two, you know, to a uniform rod and joint at this axis.
00:11
And they can rotate about this axis.
00:14
There's angle 120 degrees, right? and you are also given the length of d1, which is 1 .24, and d2 is 0 .7 meters, right? and if one, it's given, f1, it's actually 17 new, but f2 is not, is unnomese.
00:30
Maybe you need to find it out.
00:31
So first you ask, magnetium torque produced by f1.
00:34
So f1 is going this way.
00:36
The talk, of course, is the force, the force f1 times the distance, right? from the pivot to this, to the force, right? that's d1.
00:45
So the torque is just f1 times d1, right? pagant numbers, you can find out.
00:52
For force, f2, calculate the level arm.
00:56
Well, f2 is here, right? the level arm, of course, the distance here.
01:00
So that's the level arm, which is this part.
01:02
And that's given by d2 times, you know, you have found that angle.
01:08
This is 6 degrees, right? so it's just times a sign of 60 degrees.
01:13
If the network by force f1, f2 is required to be 3 .6, what should be the f2, right? so 3 .6 newton meter, this should be count clockwise, right? counterclockwise.
01:28
So you see that this f1 is counterclockwise...