A fair coin is tossed three times. Let X be the number of heads among the first two tosses and Y be the number of heads among the last two tosses. What is P(X = 1|Y = 0)? a. 1/2 b. 1/4 c. 1/8 d. None of the other answers is correct e. 3/4
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There are 2^2 = 4 possible outcomes for the last two tosses (HH, HT, TH, TT), and only one of them has no heads (TT). So, P(Y = 0) = 1/4. Now, we need to find the probability of X = 1 given Y = 0. This means there is exactly one head in the first two tosses and Show more…
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