00:02
Hi there, in this question we want to produce a certain amount of iron 3 oxide, that is 14 .2 grams, and we want to know how many grams of oxygen would be required.
00:14
Well, both of these are a mass, making this a mass -to -mass stoichiometry problem.
00:23
And in a mass -to -mass stoichiometry problem, the first thing we need is a balanced chemical equation.
00:28
So we are given an equation here, but it is not balanced, because balanced equations have the same number of each type of atom on both sides of the arrow, and this one definitely does not.
00:41
All right, to balance this i'm going to start with the oxygen.
00:45
There are two oxygen on the left, but three on the right.
00:47
The only way to make these equal would be to bump them both up to the least common multiple of 2 and 3, which is 6.
00:56
So we need 3 of the o2 and 2 of the fe2o3.
01:01
Now we have 2 times 2 or 4 iron on the right, so we need a 4 in front of the fe on the left.
01:08
All right, we are trying to produce 14 .2 grams of rust for some reason, and we want to know how many grams of oxygen had to react.
01:22
All right, so for a mass -to -mass stoichiometry problem, there are essentially three basic steps.
01:27
First step is to take the mass that you're given and convert that to moles of the substance.
01:32
So we're going to convert this to moles by using the molar mass of fe2o3.
01:38
The molar mass is the mass of one mole of the substance in grams, and we get that by adding together the individual masses from the periodic table.
01:46
So 2 times the mass of iron plus 3 times the mass of oxygen will give us the total molar mass.
01:52
Next we'll convert from moles of fe2o3 to moles of the oxygen, and we can do that by using the mole ratio.
02:02
The mole ratio is the ratio in which the two reactants, or the two substances, are found in the equation, and it's the coefficients that give us that mole ratio.
02:14
So this shows us that for every three moles of oxygen that react, we produce two moles of the product.
02:21
So we have a 3 to 2 ratio...