00:01
So for this problem, we're given this balance chemical reaction.
00:03
We're also provided the mass of the two reactants and the mass of the product produced.
00:08
We're asked to find the percent yield.
00:10
So the number given for the iron, sorry, for the ferocene is 1 .75 grams.
00:20
So that is our actual yield of ferocene.
00:23
So then we need to find out the theoretical yield.
00:26
Well, since we're given the mass of both reactants, we have to figure out which reactant is the limiting reactant.
00:33
So to do that, we're going to convert both of them to pharazine and then use that the lowest mass of those two as the theoretical yield for our actual yield or percent yield calculation.
00:45
So to start, i wrote the masses that we're starting with.
00:48
I also wrote the molecular, sorry, i also wrote the molar mass of each of those compounds.
00:55
So let's start with the nac -5h5.
00:59
So that is going to be 2 .50 grams of nac5h5.
01:07
Whatever we start with has to go on the bottom.
01:10
So grams of nac5h5 will go on the bottom.
01:15
One mole of that substance will go up top.
01:24
The molar mass is 88 .09.
01:27
Found using the periodic table.
01:30
The second step then is to get rid of our moles.
01:32
So moles of nac5h5 will go on the bottom.
01:39
Moles of pharazine will go at top.
01:47
Whenever we look at mole over mole, we need to look at the molar ratio, which means we need to look at the coefficients.
01:53
So pharazine has a coefficient of one, nac5h5 has coefficient of two.
01:59
The last step then is to multiply by the mass.
02:03
So we're going to go one mole of pharazine, and we're going to put grams of, fac 5h5h52 top, and the molar mass of that is 186 .05...