fiber glass insulating board of thermal conductivity 0.05 W/(m • °C) is to be used to limit the heat losses to 80 W/m2 for a temperature difference of 160°C across the board. Determine the thickness of the insulating board. Answer: 0.1 m
Added by Colleen S.
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05 W/(m•°C), the heat loss (Q) as 80 W/m², and the temperature difference (ΔT) as 160°C. We need to find the thickness (d) of the insulating board. We can use the formula for heat transfer through a flat surface: Q = k * (ΔT / d) * A where A is the area of the Show more…
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