Fig. P3.4 shows an electromagnet system for lifting a section of steel channel. The coil has 600 turns. The reluctance of the magnetic material can be ne- glected up to a flux density of 1.4 tesla. (a) For a coil current of 15 A (dc) determine the maximum air gap g for which the flux density is 1.4 tesla. (b) For the air gap in part (a), determine the force on the steel channel. (c) The steel channel has a mass of 1000 kg. For a coil current of 15 A, determine the largest gap at which the steel channel can be lifted magneti- cally against the force of gravity (9.81 m/secĀ²).
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- The coil has 600 turns. - The current through the coil is 15 A (DC). - The magnetic material's reluctance can be neglected up to a flux density of 1.4 Tesla. - The dimensions of the steel channel and the electromagnet setup are given, but for part (a), we Show moreā¦
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Adi S.
An electromagnet has a cross section of 20 mm x 30 mm. The relative permeability of the magnetic material is Ī¼ = 750. Its coil has N = 1000 turns. Find: ā¢ The mass that can be lifted if a flux density B = 2 T is generated. ā¢ The magnetic field energy density. ā¢ The magnetic flux Ī¦. ā¢ The magnetic field strength assuming no air gap. ā¢ The required current I to generate the desired field strength if the length of the magnetic circuit assuming no air gap is 50 mm. The permeability of free space Ī¼ā = 4Ļ Ć 10ā»ā· HĀ·mā»Ā¹. The acceleration of gravity is g = 9.8 m/sĀ².
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