Question

Figure 2 signal (a.u.) 0 10 20 30 40 50 60 1 2 3 5 4 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 time (min) 20. Assuming the component yielding peak 1 is not retained by the stationary phase, how much time does the component yielding peak 3 spend in the stationary phase? a) 2.2 min b) 1.8 min c) 1.4 min d) 1.0 min e) 0.6 min 21. Assuming Figure 2 resulted from a reversed phase LC separation using 50% ethanol in water as the mobile phase, repeating the analysis with 75% ethanol will result in a) increased peak areas b) decreased peak areas c) shorter retention times d) longer retention times

          Figure 2
signal (a.u.)
0 10 20 30 40 50 60
1
2
3
5
4
0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
time (min)
20. Assuming the component yielding peak 1 is not retained
by the stationary phase, how much time does the component
yielding peak 3 spend in the stationary phase?
a) 2.2 min b) 1.8 min c) 1.4 min d) 1.0 min e) 0.6 min
21. Assuming Figure 2 resulted from a reversed phase
LC separation using 50% ethanol in water as the mobile
phase, repeating the analysis with 75% ethanol will result
in
a)
increased peak areas
b)
decreased peak areas
c)
shorter retention times
d)
longer retention times

Figure 2
signal (a.u.)
0 10 20 30 40 50 60
1
2
3
5
4
0 0.5 1.0 1.5 2.0 2.5 3.0 3.5
time (min)
20. Assuming the component yielding peak 1 is not retained
by the stationary phase, how much time does the component
yielding peak 3 spend in the stationary phase?
a) 2.2 min b) 1.8 min c) 1.4 min d) 1.0 min e) 0.6 min
21. Assuming Figure 2 resulted from a reversed phase
LC separation using 50% ethanol in water as the mobile
phase, repeating the analysis with 75% ethanol will result
in
a)
increased peak areas
b)
decreased peak areas
c)
shorter retention times
d)
longer retention times

Added by Catherine M.

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