Figure 2 shows the Zener diode is used as a voltage...

Figure 2 shows the Zener diode is used as a voltage regulator. R is 50? and the Zener diode is rated at 3W and VZ is 20V. a) What is the purpose of voltage regulator? b) If V1 is 40V and by assuming IZ(min) and rZ are zero, over what range of IL do we have regulation? Over what range which RL can be varied with constant load voltage? c) If RL is kept constant with a value of 70?, over what range of V1 do we have regulation? d) If rZ is 5?, what is the range of load voltage in regulation?

Transcript

00:01 Hello in this question we have given scenario looks like this is genadiod this is 2 port this is i1 this is v1 riz and this is load r current is il and given r equal to 50 om and pz p .j .d equal to 3 watt and vj equal to 20 volts.

00:52 Okay, in a part we have to find that what is the purpose of voltage regulator.

00:57 Okay, so the voltage regulator generate a fixed output voltage of a constant magnitude irrespective of changes to its input voltage voltage or load condition so this is answer for the first part why we required voltage regulator now moving forward further to b part in b part if v1 is 40 volt and by assuming iz and rz r0 our word range of il we do have regulation our what range of rl we can be varied the constant load voltage okay so we for that we have given p j is equal to i z v z that is equal to by this i z we will be p z upon v z that will be 3 by 20 this will come 0 .15 ampere okay if even equal to 40 weld i z minimum o rz will be 0 now in this condition the circuit looks like this plus minus this is 40, this is 50 -oom, here is 20 volt in this position and this is our genoid and this is variable resistant rz.

02:59 So rl minimum will be rvz vz, v minus vz.

03:05 This will be 50 into 20 divided by 20.

03:11 So rlz minimum that will be 50 -hom.

03:17 Now moving further is will be v1 minus vz divided by r that is 40 minus 20 divided by 50 this will come 0 .4 ampia so il minimum will be is minus izm that is 0 .4 minus i zm that is 0 .4 minus 0 .15 this is our iz here we calculated to put that in that value and we will get 0 .25 ampia il minimum for that rl maximum will be vz il minimum that will be 20 divided by 0 .25 that is 80 off so our il max will be i s minus i z minimum i z minimum is 0 so i'll max will be 0 .4 oh this is our answer for the b bar moving further to c part in c part if rl is kept constant with the value of 70 om or what range of v1 we do have regulation for that circuit looks like this this is v that is v that is vs this is our g -dode diode this is rl given rl equal to 70 on r s equal to r you have vz so vs minimum that is vth so v -th will be vs rl divided by rs plus rl into that is equal to into vj...

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