Figure 25-35 shows a variable "air gap" capacitor for manual tuning. Alternate plates are connec

Name: Figure 25-35 shows a variable "air gap" capacitor for manual tuning. Alternate plates are connected together; one group of plates is fixed in position, and the other group is capable of rotation. Consider a capacitor of n=8 plates of alternating polarity, each plate having area A=1.25 cm^2 and separated from adjacent plates by distance d=3.40 mm . What is the maximum capacitance of the device?
Uploaded: 2022-07-02T01:27:18-08:00
Duration: 2 min 13 s
Channel: Ivan Kochetkov
Description: Figure 25-35 shows a variable "air gap" capacitor for manual tuning. Alternate plates are connected together; one group of plates is fixed in position, and the other group is capable of rotation. Consider a capacitor of n=8 plates of alternating polarity, each plate having area A=1.25 cm^2 and separated from adjacent plates by distance d=3.40 mm . What is the maximum capacitance of the device?

Step 1: Calculate the capacitance of an individual capacitor using the formula ( C = frac{{varep

Question

Figure $25-35$ shows a variable "air gap" capacitor for manual tuning. Alternate plates are connected together; one group of plates is fixed in position, and the other group is capable of rotation. Consider a capacitor of $n=8$ plates of alternating polarity, each plate having area $A=1.25 \mathrm{~cm}^{2}$ and separated from adjacent plates by distance $d=3.40 \mathrm{~mm} .$ What is the maximum capacitance of the device?

          Figure $25-35$ shows a variable "air gap" capacitor for manual tuning. Alternate plates are connected together; one group of plates is fixed in position, and the other group is capable of rotation. Consider a capacitor of $n=8$ plates of alternating polarity, each plate having area $A=1.25 \mathrm{~cm}^{2}$ and separated from adjacent plates by distance $d=3.40 \mathrm{~mm} .$ What is the maximum capacitance of the device?

Added by David A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

07/02/2022

Step 1

85 \times 10^{-12} \, \text{F/m} \) is the permittivity of free space. Substitute the given values: $ C = \frac{{8.85 \times 10^{-12} \, \text{F/m} \times 1.25 \times 10^{-4} \, \text{m}^2}}{{3.40 \times 10^{-3} \, \text{m}}} $ \( C = \frac{{1.10625 \times Show more…

Show all steps

Thanks for your feedback!

Figure $25-35$ shows a variable "air gap" capacitor for manual tuning. Alternate plates are connected together; one group of plates is fixed in position, and the other group is capable of rotation. Consider a capacitor of $n=8$ plates of alternating polarity, each plate having area $A=1.25 \mathrm{~cm}^{2}$ and separated from adjacent plates by distance $d=3.40 \mathrm{~mm} .$ What is the maximum capacitance of the device?