Question

FIGURE 4 shows (R_{1}=10Omega), (R_{2}=12Omega), and (R_{3}=5Omega) are connected to a 15V power supply. Calculate the (i) effective resistance. [Ans: 13.53Omega] (ii) potential difference across (R_{3}). [3.91 V]

Name: figure 4 shows r110omega r212omega and r35omega are connected to a 15v power supply calculate the i effective resistance ans 1353omega ii potential difference across r3 391 v 54405
Uploaded: 2022-06-08T06:21:43-08:00
Duration: 2 min 36 s
Channel: Ivan Kochetkov
Description: figure 4 shows r110omega r212omega and r35omega are connected to a 15v power supply calculate the i effective resistance ans 1353omega ii potential difference across r3 391 v 54405

          FIGURE 4 shows (R_{1}=10Omega), (R_{2}=12Omega), and (R_{3}=5Omega) are connected to a 15V power supply. Calculate the
(i) effective resistance. [Ans: 13.53Omega]
(ii) potential difference across (R_{3}). [3.91 V]

figure 4 shows r110omega r212omega and r35omega are connected to a 15v power supply calculate the i effective resistance ans 1353omega ii potential difference across r3 391 v 54405

Added by Gregory C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

06/08/2022

Step 1

To calculate the effective resistance of the circuit, we can use the formula for resistors in parallel: \(\frac{1}{R_{\text{eff}}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}\) Substitute the given values: \(\frac{1}{R_{\text{eff}}} = \frac{1}{10} + Show more…

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FIGURE 4 shows (R_{1}=10Omega), (R_{2}=12Omega), and (R_{3}=5Omega) are connected to a 15V power supply. Calculate the (i) effective resistance. [Ans: 13.53Omega] (ii) potential difference across (R_{3}). [3.91 V]