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• Example: Figure Q.1 shows an iron core transformer having a uniform cross-section and a small air gap in the centre leg. The relevant data are: $N_1 = 200, N_2 = 100, I_1 = 10 A, l_1 = 20 cm, g = 2 mm, l_2= 5 cm$. Area of cross-section $S = 4 cm^2$, $\mu_r$ of core = 500. (a) Sketch the equivalent circuit in terms of mmf and reluctances. (b) Determine the flux and flux density in the gap g. (c) Determine the flux linkage with the secondary winding with $N_2$ turns. 0.1146 Wb) (Ans. 0.208 mWb, 0.52 T;

          • Example:
Figure Q.1 shows an iron core transformer having a uniform
cross-section and a small air gap in the centre leg. The relevant
data are:
$N_1 = 200, N_2 = 100, I_1 = 10 A, l_1 = 20 cm, g = 2 mm, l_2= 5 cm$.
Area of cross-section $S = 4 cm^2$, $\mu_r$ of core = 500.
(a) Sketch the equivalent circuit in terms of mmf and reluctances.
(b) Determine the flux and flux density in the gap g.
(c) Determine the flux linkage with the secondary winding with $N_2$
turns.
0.1146 Wb)
(Ans. 0.208 mWb, 0.52 T;

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• Example:
Figure Q.1 shows an iron core transformer having a uniform
cross-section and a small air gap in the centre leg. The relevant
data are:
N1 = 200, N2 = 100, I1 = 10 A, l1 = 20 cm, g = 2 mm, l2= 5 cm.
Area of cross-section S = 4 cm^2, of core = 500.
(a) Sketch the equivalent circuit in terms of mmf and reluctances.
(b) Determine the flux and flux density in the gap g.
(c) Determine the flux linkage with the secondary winding with N2
turns.
0.1146 Wb)
(Ans. 0.208 mWb, 0.52 T;

Added by Philip P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Krishna J

Step 1

- Number of turns in the primary winding, \(N_1 = 200\). - Number of turns in the secondary winding, \(N_2 = 100\). - Current in the primary winding, \(I_1 = 10A\). - Length of the magnetic path in the core, \(l_1 = 20cm = 0.2m\). - Length of the air gap, \(g = Show more…

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Figure Q. 1 shows an iron core transformer having a uniform cross-section and a small air gap in the center leg. The relevant data are: N1=200, N2=100, I1=10A, l1=20cm, g=2mm, l2=5cm. Area of cross-section S=4cm^2, μr of core=500. (a) Sketch the equivalent circuit in terms of mmf and reluctances. (b) Determine the flux and flux density in the gap g. (c) Determine the flux linkage with the secondary winding with N2 turns. (Ans. 0.208mWb, 0.52T; 0.1146Wb)

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