2.6. The load shown in Figure 2.22 consists of a resistance R in parallel with a capacitor of reactance X. The load is fed from a single-phase supply through a line of impedance $8.4 + j11.2 \Omega$. The rms voltage at the load terminal is $1200/0^{\circ} V$ rms, and the load is taking 30 kVA at 0.8 power factor leading. (a) Find the values of R and X. (b) Determine the supply voltage V.
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From the given information, we know that the voltage across the resistor (R) is 8.4 + j11.2 V. We can represent this voltage as a complex number: V_R = 8.4 + j11.2 V. Since the voltage across the resistor is the same as the supply voltage (V), we can say that V Show more…
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