Question

Fill in the matrix in the equation below to find the line that passes through points $(-3, -4)$ and $(0, 2)$. $\det \begin{bmatrix} x & 5 \\ -3 & -4 \end{bmatrix} = 0$ What is the equation of the line that passes through points $(-3, -4)$ and $(0, 2)$? y = x +

          Fill in the matrix in the equation below to find the line that passes through points $(-3, -4)$ and $(0, 2)$.
$\det \begin{bmatrix} x & 5 \\ -3 & -4 \end{bmatrix} = 0$
What is the equation of the line that passes through points $(-3, -4)$ and $(0, 2)$?
y = x +
        
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Fill in the matrix in the equation below to find the line that passes through points (-3, -4) and (0, 2).
< b m a t r i x >
 = 0
What is the equation of the line that passes through points (-3, -4) and (0, 2)?
y = x +

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Fill in the matrix in the equation below to find the line that passes through points (-3,-4) and (0,2). det[[ Ex: 5,,],[,-4,],[,,]]=0 What is the equation of the line that passes through points (-3,-4) and (0,2) ? y=,x+ Fill in the matrix in the equation below to find the line that passes through points (-3, --4) and (0, 2) Ex: 5 det What is the equation of the line that passes through points (-3, -4) and (0, 2)? y=Ex:5
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Transcript

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00:01 So i want to find the slope of a line that goes through the following points.
00:05 My first point is 1, negative 2, and my second point is 4 -3.
00:21 This is 4 -4 -9 -3.
00:32 Let me see if i copied the problem correctly.
00:36 So the first step, again, is to find the slope.
00:40 So slope is the changing y.
00:46 Over my change in x or rise overrun.
00:51 So again, remember that you are labeling your points.
00:56 So when you start plurrying into the formula, you don't mess up.
01:04 So to find the slope using my two points, slope equals y2 is negative 3 minus.
01:12 And remember, you have a negative and you have a minus there.
01:15 So you're keeping both signs.
01:18 Because that is the common mistake.
01:21 And then my x2 is negative 4 minus my x1 is positive 1...
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