We have the equation:
\( -5 \log _{6} 2=\log _{6} x \)
First, we can rewrite the equation using the power rule of logarithms:
\( \log _{6} (2^{-5})=\log _{6} x \)
Now, since the bases of the logarithms are the same, we can equate the arguments:
\( 2^{-5} = x
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