Find a 3rd degree polynomial with real coefficients with zeros 3 and 4i. p(x) = (x - 3)^2(x - 4) p(x) = (x + 3)^2(x + 4) p(x) = (x - 3)(x - 4)^2 p(x) = (x - 3)(x^2 + 16) Question 25 (2.5 points) A polynomial with real coefficients has a zero of -6 - 2i. Which one of the following must also be a zero of the polynomial? 6 - 2i 2i 6 + 2i -6 + 2i
Added by Manuela P.
Close
Step 1
Since the coefficients are real, the complex conjugate of 4i, which is -4i, must also be a zero of the polynomial. Now, we have three zeros: 3, 4i, and -4i. Show more…
Show all steps
Your feedback will help us improve your experience
Supreeta N and 51 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find a polynomial with real coefficients that has the given zeros. 3 + 4i, 3 - 4i, - 1 One such polynomial P(x) can be defined as P(x) = x^3 - 5x^2 + x + 25.
Hemraj K.
Find a polynomial P(x) with real coefficients having a degree 6, leading coefficient 5, and zeros 4, 0 (multiplicity 3), and 2-4i.
Khushbu R.
Find a polynomial f(x) of degree 3 with real coefficients and the following zeros: -3 , 1-2i
Adi S.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD