00:01
Okay, so we want to find a basis of the space of matrices that satisfy this equation.
00:07
So the space of matrices to satisfy a times 11111 is equal to the zero matrix.
00:16
So let's just write a as a, b, c, d and see what we get.
00:21
So if we do this, then a times this matrix 1111, we get a, b, c, d times 1 ,1, 1 ,1, 1, 1.
00:31
Is equal to a plus b a to the first is a plus b and then again we get a plus b and then we get c plus d and again c plus d and we want this to satisfy this equation so we want this to be equal to the matrix zero zero zero so here we have four equations we have a plus b is zero a plus b is zero again and then c plus is zero and again c plus d is zero so we have four equations but two of them are the same so really we only have two equations we have a plus b is equal to zero and we have c plus d is equal to zero so we can rearrange this and write a is minus b and c and then the matrix a b c d well this has to be of the following form a is minus b b b is just b still c is minus d and d is still d.
01:37
So now if we separate this into matrices which only contain one of these variables, we have minus b, b, b, 0, 0, 0, minus d...