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Hello, the question is the trust given below is subjected to the force zone.
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This is the trust.
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Determine the force in each member of the trust and state if the members are in tension or comprehension.
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And second is finding the reaction that supports a and b.
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So first of all, this is the whole diagram.
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We take movement, taking moment, taking moment, taking moment about e.
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Okay, we are taking movement about e.
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So from here, r of a multiplied by force, that equals to 3 multiplied by 3 plus 2 multiplied by 5 and that equals to what so that equals to 9 plus 12 4 divided by this 4 this 4 this is r a so from here r a will be equals to what 5 .25 kilo neuter okay this is the value for the r a now we know that from here that r a plus r e that equals to what that equals to 3 plus 2 so from here r e will be equals to what 5 minus 5 0 .25 and therefore r .e will be equals to 0 .25 minus of 0 .25 kilo newton.
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Okay.
01:09
So what that negative sign shows? it shows the reaction of r .e.
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Is opposed.
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Okay.
01:14
Now we consider the joint a.
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Okay...