Find all distinct roots (real or complex) of z^2 + (3 + 6i)z + (-19 + 9i). Enter the roots as a comma-separated list of values of the form a + bi. Use the square root symbol '√' where needed to give an exact value for your answer. z =
Added by John R.
Step 1
The quadratic formula is given by: z = [-b ± sqrt(b^2 - 4ac)] / (2a) In this case, a = 1, b = 3 + 6i, and c = -19 + 9i. Plugging these values into the quadratic formula gives: z = [-(3 + 6i) ± sqrt((3 + 6i)^2 - 4(1)(-19 + 9i))] / (2*1) = [-3 - 6i ± sqrt((9 - Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vaidik Stats and 50 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find all complex cube roots of z= 2 + 2i. Write each number in the form a+bi.
Urvashi A.
Find all complex numbers z such that z^2 = 5 + 12i, and give your answer in the form a + bi. Use the square root symbol '√' where needed to give an exact value for your answer. z =
Hemraj K.
Find all the complex roots. Leave your answers in polar form with the argument in degrees. The complex fifth roots of $-i$
Polar Coordinates; Vectors
The Complex Plane; De Moivre's Theorem
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD