00:01
Okay, so we have some different conditions here.
00:04
We have z1 plus z2 is equal to negative 20, and we have z1 times c2 is equal to 29, and we want to find all possible solutions for z1 and z2.
00:13
We're going to start this using substitution.
00:16
I'm going to solve for z1 first.
00:18
I'm just going to subtract z2 from both sides, and i am left with z1 is equal to negative 20 minus z2.
00:28
I'm just going to substitute this value.
00:30
Into our second equation here.
00:33
So we have negative 20 minus z2 times z2 is equal to 29.
00:43
If we simplify this, this is going to give us negative 20 z2 minus z2 quantity squared is equal to 29.
00:56
I'm going to bring all the values onto one side of the equation so that we can solve the quadratic formula.
01:03
So if i add 20 z2 and z squared to both sides of my equation, i'm going to have zero is equal to z2 squared plus 20 times z2 plus 29.
01:21
Now i don't have any factors of 29 that are going to add up to 20, so we need to use the quadratic formula.
01:27
So we're going to solve for z two.
01:29
The quadratic formula tells us we take the opposite of our b value, which is 20 in this case, and we add the square root of b squared minus 4 times 1.
01:43
That's our a value times 29.
01:47
And we divide it all by 2 times a, which in this case is 1.
01:53
If we simplify this, we get z2 is equal to negative 20 plus or minus the square root...