Find all solutions of the equation 2 cos x - 1 = 0 on 0 ? x < 2?? The answers are A and B, where A < B A = B = Submit Question
Added by Paul -.
Close
Step 1
Step 1:** Add 1 to both sides of the equation: \[2\cos(\theta) + 1 = \sqrt{3} + 1\] \[2\cos(\theta) + 1 = 2\] ** Show more…
Show all steps
Your feedback will help us improve your experience
Gregory Higby and 100 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find two solutions of each equation. Give your solutions in both degrees $\left(0^{\circ} \leq \theta < 360^{\circ}\right)$ and radians $(0 \leq \theta < 2 \pi) .$ Do not use a calculator. (a) $\cos \theta=\frac{\sqrt{2}}{2}$ (b) $\cos \theta=-\frac{\sqrt{2}}{2}$
Trigonometric Functions
Trigonometric Functions of Any Angle
Find all solutions of the equation. $$2 \cos 2 \theta-\sqrt{3}=0$$
Analytic Trigonometry
Trigonometric Equations
Find all solutions of the given equation. $$2 \cos x-1=0$$
Preliminaries
Trigonometric and Inverse Trigonometric Functions
Recommended Textbooks
Precalculus with Limits
Precalculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD
