Question

Find an equation of the line tangent to the graph of f(x) = 2x^3 at (2,16). The equation of the tangent line is y = . (Type an expression using x as the variable.)

          Find an equation of the line tangent to the graph of f(x) = 2x^3 at (2,16).

The equation of the tangent line is y = .
(Type an expression using x as the variable.)

Added by Maria W.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Kathleen Carty

03/25/2023

Step 1

First, we need to find the derivative of the function f(x) = -2x^2. Using the power rule, we have: f'(x) = -4x Show more…

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Find an equation of the line tangent to the graph of f(x) = 2x^3 at (2,16). The equation of the tangent line is y = . (Type an expression using x as the variable.)