00:02
The problem asks us to find an expression for the tension in a rope with the weight attached to its center.
00:08
The force exerted by the weight is f and the angle made with a horizontal is t.
00:12
So let's try to draw the vectors here.
00:16
We have a vector to the upper left, which is your tension left, a vector to the upper right, which is your tension right, and a force directly downward from the weight, which is labeled as your force f.
00:33
And the diagram states that this angle here is labeled as t, and if these two ropes are symmetric, and then the force is placed at the center, this would be angle t as well.
00:51
And from geometry, your alternating interior angles dictates that these angles are labeled as t as well.
01:00
Now to get the tension across the rope, you need to solve for the equilibrium forces along the x and along the y.
01:11
So the equilibrium of forces along the x states that all forces along the x should be equal to zero.
01:18
F is directly is directed downwards, hence it does not have an x component...