Question

Find any relative maximum. Round answers to 4 decimal places. \[ f(x)=\frac{x^{2}+2 x-1}{x^{2}+2} \] relative maximum: \( (-0.5661,-0.7880) \) relative maximum: \( (-0.5616,-0.7808) \) relative maximum: \( (3.5616,1.2808) \) relative maximum: \( (3.3107,1.3375) \) relative maximum: \( (3.5661,1.2880) \) None of the above

          Find any relative maximum. Round answers to 4 decimal places.
\[
f(x)=\frac{x^{2}+2 x-1}{x^{2}+2}
\]
relative maximum: \( (-0.5661,-0.7880) \)
relative maximum: \( (-0.5616,-0.7808) \)
relative maximum: \( (3.5616,1.2808) \)
relative maximum: \( (3.3107,1.3375) \)
relative maximum: \( (3.5661,1.2880) \)
None of the above

Find any relative maximum. Round answers to 4 decimal places.

f(x)=(x^2+2 x-1)/(x^2+2)

relative maximum: (-0.5661,-0.7880)
relative maximum: (-0.5616,-0.7808)
relative maximum: (3.5616,1.2808)
relative maximum: (3.3107,1.3375)
relative maximum: (3.5661,1.2880)
None of the above

Added by Michael R.

Contemporary Precalculus

Thomas W. Hungerford, Douglas J. Shaw 5th Edition

Chapter 3

Instant Answer

Solved by Expert Julie Silva

Step 1

Using the quotient rule, where \( u = x^2 + 2x - 1 \) and \( v = x^2 + 2 \), we have: \[ f'(x) = \frac{u'v - uv'}{v^2} \] First, compute \( u' \) and \( v' \): \[ u' = 2x + 2 \] \[ v' = 2x \] Now, apply the quotient rule: \[ f'(x) = \frac{(2x + 2)(x^2 + 2) - Show more…

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Find any relative maximum. Round answers to 4 decimal places. \[ f(x)=\frac{x^{2}+2 x-1}{x^{2}+2} \] relative maximum: \( (-0.5661,-0.7880) \) relative maximum: \( (-0.5616,-0.7808) \) relative maximum: \( (3.5616,1.2808) \) relative maximum: \( (3.3107,1.3375) \) relative maximum: \( (3.5661,1.2880) \) None of the above