Step 1:
Rewrite the equation in standard form by completing the square:
$(x^2 - 6x) - (y^2 + 14y) - 49 = 0$
$(x^2 - 6x + 9) - (y^2 + 14y + 49) - 49 + 9 - 49 = 0$
$(x - 3)^2 - (y + 7)^2 = 89$
$\frac{(x - 3)^2}{89} - \frac{(y + 7)^2}{89} = 1$
Show more…