Question

Find $I_o$ in the network in the figure below using source transformation. 4 k$\Omega$ $I_o$ 4 k$\Omega$ 2 k$\Omega$ 8 mA +4 V 2 k$\Omega$ 6 k$\Omega$ 4 k$\Omega$ $I_o = \boxed{.191}$ mA

          Find $I_o$ in the network in the figure below using source transformation.
4 k$\Omega$
$I_o$
4 k$\Omega$
2 k$\Omega$
8 mA
+4 V
2 k$\Omega$
6 k$\Omega$
4 k$\Omega$
$I_o = \boxed{.191}$ mA

Find Io in the network in the figure below using source transformation.
4 kΩ
Io
4 kΩ
2 kΩ
8 mA
+4 V
2 kΩ
6 kΩ
4 kΩ
Io = .191 mA

Added by Jorge B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Krystal K

Step 1

We can do this by multiplying the current source value (8mA) by the resistance in parallel with it (6kΩ). This gives us a voltage source of 48V in series with a 6kΩ resistor. Show more…

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