00:01
Here in this circuit diagram for which we have to find out the current flowing through that circuit using the superposition theorem.
00:20
So the diagram which is given to us is as follows.
00:24
Here according to this diagram which is flowing through this 10 volt source and through 10 ohm resistance.
00:38
For this we can redraw this diagram as here we will have 10 volt voltage, 1 ohm in this side, 10 ohm here, 2 ohm this side and 4 ampere will be neglected for this side.
01:05
So this will be a direct connection where we will have 5 ohm.
01:10
Now from this diagram we can find the nodal voltage which is represented as v1.
01:22
So v1 can be written as v1 -10 upon 1 plus v1 upon 10 plus v1 upon 2 plus 5 that will be equal to 0.
01:41
For finding out the lc that will be 70.
01:45
So we will write 70 v1 -700 plus 7 v1 plus 10 v1.
01:54
70 will go this side and will become 0 and 700 will come to the rhs side so it will be plus 700.
02:03
We can rewrite this equation as 70 v1 plus 17 v1 that will be equal to 700 and from here we can get the value of v1 as 700 upon 87.
02:14
So this is the value of nodal voltage.
02:19
Now next we can find out the current which is flowing through this 10 ohm resistor and it can be found using the formula i which is equal to v1 upon 2 plus 5.
02:42
So we have found out the value for v1 that is 700 upon 87 multiplied to 7...